import numpy as np
import matplotlib.pyplot as plt
%matplotlib inline
plt.rcParams['figure.dpi'] = 120
plt.rcParams['figure.figsize'] = [10,5]
plt.rcParams['axes.grid'] = True
import quandl as qdl
from pandas.plotting import register_matplotlib_converters
#plt.rcParams.keys()
register_matplotlib_converters()
#warnings.warn(msg, FutureWarning)
data = qdl.get("WSE/WIG30")
plt.plot(data['High'])
plt.show()
Wig_on_high = data['High']
Low, High = np.min(Wig_on_high.array), np.max(Wig_on_high.array)
print(Low, High)
Wig_on_high.index
from scipy.stats import gaussian_kde
smoothed = gaussian_kde(Wig_on_high.array) # create an object containing the data
val = np.linspace(Low-100, High+100, 1000)
plt.hist(Wig_on_high, bins=np.linspace(Low, High, 40), density='True', label='generated dist.', facecolor='green', alpha=0.25, edgecolor='black', linewidth=1.2)
smoothed_val = smoothed(val)
plt.plot(val, smoothed_val)
plt.show()
1997.93 3041.25
Value below which there is $\alpha$ data out of the whole data.
$$VaR_\alpha: \int_0^{VaR_\alpha} \rho(x)dx = \alpha$$where $\rho(x)$ is a distribution. For normal distribution
$$VaR_\alpha={\displaystyle \mu +\sigma {\sqrt {2}}\operatorname {erf} ^{-1}(2\alpha-1)}$$normalization = np.sum(smoothed_val)
y = smoothed_val/(normalization)
cum_y = np.cumsum(y)
plt.plot(val, cum_y)
plt.plot(val, y/np.max(y))
[<matplotlib.lines.Line2D at 0x7f05543535f8>]
level = 10/100
risk = len(val[cum_y<level]) # index of level risk
VaR = val[risk] # value at risk
print(f"VaR({level*100:.1f}%) = {VaR:.2f}")
VaR(10.0%) = 2358.42
plt.plot(val, cum_y)
plt.plot(val, y/np.max(y))
plt.fill_between(val[0:risk], 0, y[0:risk]/np.max(y), color='red', alpha = 0.20)
plt.plot(val[0:risk], y[0:risk]/np.max(y), 'r')
[<matplotlib.lines.Line2D at 0x7f0554296be0>]
Calculate VaR direcly from the bins from the histogram. Write a function which iteratively adjusts number and bin positions for given $\alpha$
Calculate the daily VaR rom WIG data (use histogram for daily relative differences $\displaystyle \frac{y_{t}-y_{t-1}}{y_{t-1}}$.
quad
to integrate and fsolve
to solve appropriate equation). Fast Fourier Transform (FFT):
$${\begin{matrix}X_{k}&=&\sum \limits _{m=0}^{N/2-1}x_{2m}e^{-{\frac {2\pi i}{N}}(2m)k}+\sum \limits _{m=0}^{N/2-1}x_{2m+1}e^{-{\frac {2\pi i}{N}}(2m+1)k}\end{matrix}} = F_k(X_0, X_2,\ldots)+e^{-2\pi ik/N}F_k(X_1, X_3,\ldots)$$But also
$${\begin{matrix}X_{k+N/2}&=&\sum \limits _{m=0}^{N/2-1}x_{2m}e^{-{\frac {2\pi i}{N}}(2m)k}+\sum \limits _{m=0}^{N/2-1}x_{2m+1}e^{-{\frac {2\pi i}{N}}(2m+1)k}\end{matrix}} = F_k(X_0, X_2,\ldots)-e^{-2\pi ik/N}F_k(X_1, X_3,\ldots)$$Instead of 2 sums over $N$ variables we need to calculate two sums over $N/2$ vars.
It can be done recursively reducing complexity $\mathcal{O}(N^2)\to\mathcal{O}(N\log_2N)$
There are algorithms which are generalized but works best for $2^n3^m5^k$
def power_spectrum(signal, T):
N = len(signal)
fft = np.fft.rfft(signal)
power_spect = np.abs(fft)*2/N
power_spect[0] /= 2
fft_freqs = np.linspace(0, np.pi/(t[1]-t[0]), len(power_spect), endpoint=False)
return fft_freqs, power_spect
N = 1001
T = 2*np.pi
t = np.linspace(0, T, N, endpoint=True)
y=np.empty([N, 4])
y[:,0]= 1+np.sin(10*t)+0.5*np.cos(20*t)
y[:,1] = np.cos(30.5*t)
y[:,2] = np.cos(40*t)*np.exp(-0.5*t)
y[:, 3] = np.cos(1005*t)
y_fft = np.empty([N//2+1, 4])
for n in range(4):
freqs, y_fft[:,n] = power_spectrum(y[:,n], T)
for n in range(4):
freqs, y_fft[:,n] = power_spectrum(y[:,n], T)
plt.fill_between(freqs, y_fft[:,n], step="mid", alpha=0.2, color='C'+str(n))
plt.step(freqs, y_fft[:,n], where='mid', color='C'+str(n))
plt.xlim(0, 50)
#plt.step(fft_freqs, power_spectrum, where='mid', color='black')
plt.xlabel('Frequency')
plt.ylabel('Power')
plt.legend(['matching', 'inacurate', 'damped', 'aliased'])
plt.show()
For $x_n=\exp(2\pi ik'n/N)$ we obtain:
$$X_{k}=\sum _{n=0}^{N-1}\exp\left[\frac{2\pi i(k'-k)n}{N}\right]=\sum _{n=0}^{N-1}q^n=\frac{1-q^N}{1-q}$$If $k'\in \mathbb{N}$ then $q^N=1$ and $X_k=\delta_{kk'}$
if $k'\notin \mathbb{N}$ then $\displaystyle |X_k|\sim \frac{1}{k-k'}$
if $k'>N$ than $x_n$ is aliased $k'\to k'\mod{N}$
For better visual properties sometimes the data are multiplied by a window
$$x_n\to w_nx_n$$The most popular windows are:
import scipy.signal as sg
N = 1000
n = np.arange(N)
for k, window in enumerate([sg.blackman, sg.triang, sg.parzen, sg.hamming]):
plt.subplot(2, 2, k+1)
plt.plot(n, window(N), label=window.__name__, color='C'+str(k))
plt.legend()
Y = np.cos(100.5*t)+np.sin(200.1632546*t)+np.sin(300*t)
freqs, Y_fft = power_spectrum(Y, T)
window = sg.blackman(Y.size)
Yw = Y*window
freqs, Yw_fft = power_spectrum(Yw, T)
plt.semilogy(freqs, Y_fft)
plt.semilogy(freqs, Yw_fft)
plt.legend(['pure FFT', 'FFT through a window'])
<matplotlib.legend.Legend at 0x7f0555dc2710>
from scipy.stats import norm
def brownian_motion(σ=2, T=10, N=1000):
t = np.linspace(0, T, N)
dt = t[1]-t[0]
r = norm.rvs(size=t.shape, scale=σ**2*dt)
x = np.cumsum(r) # used cumulative sum instead of loop
return x
M = 10000
brown = brownian_motion(N=M)
s = np.arange(M)
plt.plot(s, brown)
[<matplotlib.lines.Line2D at 0x7f053ab795f8>]
freqs, brown_fft = power_spectrum(brown, T)
plt.loglog(freqs[2:], brown_fft[2:], 'brown')
a=plt.loglog(freqs[2:], 2e-1/freqs[2:], 'green')
a = plt.plot(Wig_on_high, 'b', lw = 0.8)
fft = np.fft.rfft(Wig_on_high)
fft[20:] = 0 # we leave only first 20 frequencies - low frequency filter
ifft = np.fft.irfft(fft)
a = plt.plot(Wig_on_high.index, ifft, 'r')
t = np.linspace(0, 2*np.pi, 10000)
sig = np.sin(100*t*(1+t*t)) + np.cos(2000*t*(1+0.1*np.sin(t)))
powerSpectrum, freqenciesFound, time, imageAxis = plt.specgram(sig, Fs=10000, noverlap=128)
# Better frequency resolution
powerSpectrum, freqenciesFound, time, imageAxis = plt.specgram(sig, Fs=10000, noverlap=128, NFFT=1024)
# Better time resolution
powerSpectrum, freqenciesFound, time, imageAxis = plt.specgram(sig, Fs=10000, noverlap=16, NFFT=32)
plt.subplot(2,1,1)
plt.plot(Wig_on_high, 'b')
plt.legend(['non stationary'])
plt.subplot(2,1,2)
plt.plot(Wig_on_high.index[1:], np.diff(Wig_on_high.array), 'r')
plt.legend(['~ stationary'])
<matplotlib.legend.Legend at 0x7f0554164be0>
Smoothing - better to see the trends
Simple moving average (window size = $M$)
$$Y_i = \frac{1}{M}\sum_{j=i-M}^i X_j$$
More general weighted averages
$$Y_i = \frac{1}{M}\sum_{j=i-M}^i w_jX_j$$
with different types of windows (gaussian, triangular, Parzen, triangular etc)
Exponential smoothing
$$Y_i = \alpha X_i+(1-\alpha)Y_{i-1}$$
from sklearn.metrics import mean_absolute_error
def plot_moving_average(series, window, plot_intervals=False, scale=1.96):
rolling_mean = series.rolling(window=window).mean()
plt.figure(figsize=(12,6))
plt.title('Moving average\n window size = {}'.format(window))
plt.plot(rolling_mean, 'g', label='Rolling mean trend')
#Plot confidence intervals for smoothed values
if plot_intervals:
mae = mean_absolute_error(series[window:], rolling_mean[window:])
deviation = np.std(series[window:] - rolling_mean[window:])
lower_bound = rolling_mean - (mae + scale * deviation)
upper_bound = rolling_mean + (mae + scale * deviation)
plt.plot(upper_bound, 'r--', label='Upper bound / Lower bound')
plt.plot(lower_bound, 'r--')
plt.plot(series[window:], label='Actual values')
plt.legend(loc='best')
plot_moving_average(data.High, 30)
plot_moving_average(data.High, 90, plot_intervals=True)
### Tripple crossover method
def tripple_crossover_plot(series):
r20 = series.rolling(window=20, center=False).mean()
r50 = series.rolling(window=50, center=False).mean()
r200 = series.rolling(window=200, center=False).mean()
plt.plot(series, 'black', lw=0.8)
plt.plot(r20); plt.plot(r50); plt.plot(r200)
plt.legend(['real data', '20 day SMA', '50 day SMA', '200 day SMA'])
plt.show()
tripple_crossover_plot(Wig_on_high)
import pandas as pd
plt.plot(Wig_on_high, 'b', linewidth=0.8, alpha=0.5)
y1 = pd.DataFrame.rolling(Wig_on_high, window=30, center=True).mean()
y2 = pd.DataFrame.rolling(Wig_on_high, window=60, center=True, win_type='triang').mean()
plt.plot(y1, 'r')
plt.plot(y2, 'g')
[<matplotlib.lines.Line2D at 0x7f053b6f59e8>]
exp1 = Wig_on_high.ewm(span=20, adjust=False).mean()
exp2 = Wig_on_high.ewm(span=50, adjust=False).mean()
plt.plot(Wig_on_high, 'b', linewidth=0.5, alpha=0.5)
plt.plot(exp1)
plt.plot(exp2)
a= plt.legend(['real', '20-day', '50-day'])
Continuous version: $${\displaystyle R_{ff}(\tau )=\int _{-\infty }^{\infty }f(t+\tau ){\overline {f(t)}}\,{\rm {d}}t=\int _{-\infty }^{\infty }f(t){\overline {f(t-\tau )}}\,{\rm {d}}t}$$
from statsmodels.graphics.tsaplots import plot_acf
def auto_example1():
Y = np.cos(4*t)
fig, ax = plt.subplots(figsize=(10, 2.5))
plt.figure(figsize=(10,2.5))
a = plt.plot(t,Y)
plot_acf(Y, lags=Y.size-1, ax=ax)
auto_example1()
# nonstationary process
a = plot_acf(Wig_on_high, lags=Wig_on_high.size-1)
# stationary process
y = np.diff(Wig_on_high)
a = plot_acf(y, lags=y.size-1)
Let us consider a model: $y_{t}=\rho y_{t-1}+u_{t}\,$ where $\rho$ is a certain constant and $u_t$ is a random variable.
The model generates a non-stationary series if $\rho=1$ (there exists a s unit root)
Test for unit root:
Augmented Dickey–Fuller test $$\Delta y_t = \alpha + \beta t + \gamma y_{t-1} + \delta_1 \Delta y_{t-1} + \cdots + \delta_{p-1} \Delta y_{t-p+1} + u_t, $$
import statsmodels
from statsmodels.tsa.stattools import adfuller
help(adfuller)
Help on function adfuller in module statsmodels.tsa.stattools: adfuller(x, maxlag=None, regression='c', autolag='AIC', store=False, regresults=False) Augmented Dickey-Fuller unit root test The Augmented Dickey-Fuller test can be used to test for a unit root in a univariate process in the presence of serial correlation. Parameters ---------- x : array_like, 1d data series maxlag : int Maximum lag which is included in test, default 12*(nobs/100)^{1/4} regression : {'c','ct','ctt','nc'} Constant and trend order to include in regression * 'c' : constant only (default) * 'ct' : constant and trend * 'ctt' : constant, and linear and quadratic trend * 'nc' : no constant, no trend autolag : {'AIC', 'BIC', 't-stat', None} * if None, then maxlag lags are used * if 'AIC' (default) or 'BIC', then the number of lags is chosen to minimize the corresponding information criterion * 't-stat' based choice of maxlag. Starts with maxlag and drops a lag until the t-statistic on the last lag length is significant using a 5%-sized test store : bool If True, then a result instance is returned additionally to the adf statistic. Default is False regresults : bool, optional If True, the full regression results are returned. Default is False Returns ------- adf : float Test statistic pvalue : float MacKinnon's approximate p-value based on MacKinnon (1994, 2010) usedlag : int Number of lags used nobs : int Number of observations used for the ADF regression and calculation of the critical values critical values : dict Critical values for the test statistic at the 1 %, 5 %, and 10 % levels. Based on MacKinnon (2010) icbest : float The maximized information criterion if autolag is not None. resstore : ResultStore, optional A dummy class with results attached as attributes Notes ----- The null hypothesis of the Augmented Dickey-Fuller is that there is a unit root, with the alternative that there is no unit root. If the pvalue is above a critical size, then we cannot reject that there is a unit root. The p-values are obtained through regression surface approximation from MacKinnon 1994, but using the updated 2010 tables. If the p-value is close to significant, then the critical values should be used to judge whether to reject the null. The autolag option and maxlag for it are described in Greene. Examples -------- See example notebook References ---------- .. [*] W. Green. "Econometric Analysis," 5th ed., Pearson, 2003. .. [*] Hamilton, J.D. "Time Series Analysis". Princeton, 1994. .. [*] MacKinnon, J.G. 1994. "Approximate asymptotic distribution functions for unit-root and cointegration tests. `Journal of Business and Economic Statistics` 12, 167-76. .. [*] MacKinnon, J.G. 2010. "Critical Values for Cointegration Tests." Queen's University, Dept of Economics, Working Papers. Available at http://ideas.repec.org/p/qed/wpaper/1227.html
res = adfuller(Wig_on_high)
print(res)
if res[1]>0.05:
print("The series is not stationary") # we cannot reject that there is a unit root
else:
print("The series is stationary")
(-2.787517907694647, 0.06007898539491691, 1, 784, {'1%': -3.4387184182983686, '5%': -2.865233578638179, '10%': -2.5687368149338816}, 6876.424718535679) The series is not stationary
res = adfuller(np.diff(Wig_on_high))
print(res)
if res[1]>0.05:
print("The series is not stationary") # we cannot reject that there is a unit root
else:
print("The series is stationary")
(-24.541339810293543, 0.0, 0, 784, {'1%': -3.4387184182983686, '5%': -2.865233578638179, '10%': -2.5687368149338816}, 6873.830259980225) The series is stationary
Calculate VaR direcly from the bins from the histogram. Write a function which iteratively adjusts number and bin positions for given $\alpha$
Calculate the daily VaR rom WIG data (use histogram for daily relative differences $\displaystyle \frac{y_{t}-y_{t-1}}{y_{t-1}}$.
Write a function calculating VaR for distribution given by analytic function (use quad
to integrate and fsolve
to solve appropriate equation).
Check if WIG is a brownian motion.